Need instructions on how to factorise (not factor!) an expression on TI nspire CX

SOLVED Hi, I solved it in my logbook, talk to me and I will show you the solution Regards, Danilo R.

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saya menyukai matematika dan beberapa kali mendapar nilai hampir sempurna di matematika. saya akan membantu anda menyelesaikan soal matematika sd hingga sma Relevant Skills and Experience saya senang menyelesaikan soal matematika

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x-x^4/8=0 =>x(1-x^3/8)=0 => x = 0, x^3/8 -1 = 0 => x = 0, x=2 Do you need to algorithm/programming? if so, algorithm is different. should consider the roots for the blow equitation: i can give a detailed program instruction for you if bid succeed.

Hi, I can able to give answer with instructions on this window however, i would be happy if you offer development stuff in this respect or any other DB, .NET, C# related technologies. Answer for your query is 2 only step 1: X-( X^4)/8=0 Step 2: take LCM then you will be reaching( 8X-X^4)/8=0 Step3: Cross multiplication 8X-X^4=0 Step 4: sign change and equation happens here so 8X=X^4 Step 5: X^4/X=8 ( trying to arrive value for X ) Step6: X^4-1=8 ( here x is in the division so we need to deduct the DR value from NR- numerator X which is X^4- X) Step7: X^3 = 8 Step8: X^3=2^3 so the answer is X =2 ( both has same power which get cancelled to reach X value) Hurray! thanks for reading, Kindly let me know if you need more explanations.

I completed Msc in science. I hope I will can to complete your prospect. So I can get this reword.f(x)=x-x^4/8=0 f(0)=0-0/8=0 f(2)=2-8/8=0 That is solved

x^4-x/8=0 •factorize the expression x(x^3-1)/8=0 •multiply the two sides by 1/8 to eliminate the denominator 8 x(x^3-1)/8.1/8=0.1/8 •we get: x(x^3-1)=0 •divide the possible cases x=0 or x^3-1=0 •solving the equation x^3-1=0 we get: x=1 •so as a solution, we have: x=0 or x=1 Thank’s

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